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9v^2-68v+84=0
a = 9; b = -68; c = +84;
Δ = b2-4ac
Δ = -682-4·9·84
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-40}{2*9}=\frac{28}{18} =1+5/9 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+40}{2*9}=\frac{108}{18} =6 $
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